Java Program to find whether a number is even or odd without using modulus/division operator.

Hey there!

In this post, we will look at a Java program to find whether a number is even or odd without using modulus/division operator.

Without using the Modulus/division operator, this can be achieved by using “bitwise AND” operator.

I would recommend you to go through the below post before you continue with this.

2’s complement – Binary representation of Negative numbers in Java

Logic: When a number is applied bitwise AND(“&“) with 1, if the LSB of the result is zero then the given number is Even else it is Odd.

Here is the Java program:

package com.sample.clearurdoubt;

import java.util.Scanner;

public class OddEvenFinder {

	public static void main(String[] args) {
		
		System.out.println("Enter a number: ");
		
		Scanner input = new Scanner(System.in);
		int val = input.nextInt();
		
		System.out.println(isEven(val) ? (val + " is an Even Number.") : (val + " is an Odd Number."));
		
		input.close();
	}
	
	private static boolean isEven(int val)
	{
		if( (val & 1) == 0)
		{
			return true;
		}
		else
		{
			return false;
		}
	}

}

package com.sample.clearurdoubt;

import java.util.Scanner;

public class OddEvenFinder {

public static void main(String[] args) {

System.out.println("Enter a number: ");

Scanner input = new Scanner(System.in);

int val = input.nextInt();

System.out.println(isEven(val) ? (val + " is an Even Number.") : (val + " is an Odd Number."));

input.close();

}

private static boolean isEven(int val)

{

if( (val & 1) == 0)

{

return true;

}

else

{

return false;

}

Output:

Happy Learning :).

Please leave a reply in case of any queries.

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